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Motion in two dimensions


In order to obtain the acceleration a(t) of the particle, we determine the time derivative of its velocity vector v(t).

ax(t)i + ay(t)j = a(t) = dv(t)/dt = dvx(t)/dt i + dvy(t)/dt j

= d(1.06)/dt i + d(0.44)/dt j = 0i + 0j = 0 cm/s2

or in column notation

(
ax(t)
ay(t)
) = a(t) = dv(t)/dt = (
dvx(t)/dt
dvy(t)/dt
) = (
0
0
) cm/s2

We find that the particle has no acceleration (which we knew already since it moves with constant velocity).






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