Height y(t)
of the plastic ball
as a function of the time t/T.
α = vterm
Velocity v(t)
of the plastic ball
as a function of the time t/T.
α = vterm
In the above figures we represent graphically
the motion of the plastic ball
as it is given by our solution for the dynamical equation
of objects moving vertically in air.
The horizontal axes of the figures are in the dimensionless quantity
t/T.
The height is given in units
vtermT
which has the dimension of length.
The velocity is given in units
vterm
which has the dimension of m/s.
In the lefthand-side figure we show how the height varies with time.
The figure sets out at
t/T≅-1.5.
At first the plastic ball rises fast in time,
but then it slows down untill it reaches its maximum position.
From thereon the plastic ball starts falling towards the Earth
thereby reducing its height.
But, instead of doing so with increasing velocity
as does the solid metal ball,
the plastic ball reaches its terminal velocity
somewhere near t/T=2
and starts moving with a
constant velocity,
in which case the height decreases linearly with time
(straight line)
instead of quadratically (parabolic curve)
as for the solid metal ball.
Only near the maximum height the curve is approximately
equal to a parabolic curve.
That phenomenon was discussed in a
previous page.
In the righthand-side figure we show how the velocity varies with time.
That curve shows even better the difference with a vertically moving object
that does not suffer from air resistance.
For the latter type of objects the corresponding curve
is given by a straight line.
Here the straight part, which runs from
t/T≅-0.5
to
t/T≅+0.5,
occurs only near the maximum height of the plastic ball
where the velocity is small and hence the air resistance negligible.
From about t/T=2 on
the velocity turns even
constant
and equal to -vterm.