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Vertical motion
Buoyant force
The area S of the top surface of the cylinder
is equal to the area of the bottom surface of the cylinder.
The downward force due to the
air pressure
at the top surface of the cylinder
equals
Ftop =
pressure × area = -pair S
whereas the upward force due to the total pressure from air and liquid
at the bottom surface of the cylinder equals
Fbottom =
pressure × area =
(pair+pliquid) S
So, there are in total three forces acting on the cylinder:
the gravitational attraction from the Earth
which is given by the weight -mg,
the force of air pressure on its top surface
-pair S
and the force of the total pressure at the bottom
(pair+pliquid) S.
Since the cylinder is in equilibrium while floating,
the sum of those forces must vanish, i.e.
- mg - pair S
+ (pair+pliquid) S = 0
hence
mg = pliquid S
The pressure inside the liquid depends on the depth
d below the surface
and on the density of the liquid
ρliquid,
according to
pliquid =
dgρliquid
Consequently
mg = pliquid S =
dgρliquid S
Furthermore is the volume
Vimm
of that part of the cylinder which sticks in the liquid
equal to Vimm=dS.
On substituting this fact in the above formula, we obtain
mg = pliquid S =
gVimm ρliquid
which is clearly equal to the weight of the liquid
which is displaced by the cylinder.
More general and also for gases
this is known as
Archimedes' principle
which states that the buoyant force on an object equals
the weight of the fluid displaced by the object,
or the density of the fluid multiplied by the submerged volume
times the gravitational acceleration g.
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