The work done by the force is converted to kinetic energy.
Assuming that F
is perpendicular to the rod,
one has
Ekin
= I ω2 /2
= work done by F = 2πr1F
in the lefthand video and
Ekin
= I ω2 /2
= work done by F = 2πr2F
in the righthand video.
Hence, since r2 < r1,
we find that the final angular velocity is
slower
when the force is applied at position
r2 (righthand video)
than when it is applied at position
r1 (lefthand video).
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