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λ1=50 pt and λ2=60 pt




So, we obtain
a = ωt-kx = 11.5t - 0.115x

     and     

b = (Δωt - Δkx)/2 = 1.0t - 0.010x


The total displacement due to the two interfering disturbances is thus given by

u(x,t) = 2A cos(1.0t-0.010x) sin(11.5t-0.115x)


In the next page we will interpret our result.





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