In order to obtain the velocity
v(t) of the particle,
we determine the time derivative of its position vector
r(t).
vx(t)i +
vy(t)j
= v(t)
= dr(t)/dt
= dx(t)/dt
i
+ dy(t)/dt
j
= d(1.06t-3.18)/dt
i
+ d(0.44t+1.70)/dt
j
= 1.06i
+ 0.44j cm/s
or in column notation
|
(
|
|
)
|
= v(t) =
dr(t)/dt =
|
(
|
|
)
|
=
|
(
|
|
)
|
cm/s
|
We find that the particle has a constant velocity (which we knew already)
with vx
component 1.06 cm/s
and vy
component 0.44 cm/s.
|
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