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Free fall with initial velocity


The velocity v of the particle is given by the relation of its time derivative to the acceleration.

(
dvx/dt
dvy/dt
) = dv/dt = a = (
0
-g
) = - (
0
g
) = - g

The differential equation dvx/dt = 0 is solved by

vx = v0x

v0x represents the x component of the initial velocity v0.

The differential equation dvy/dt = -g is solved by

vy = v0y - gt

v0y represents the y component of the initial velocity v0.

We end up with

v(t) = (
v0x
v0y - gt
) = (
v0x
v0y
) - (
0
g
) t = v0 - gt






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