In the above video we have attached the
acceleration vector a to the particle,
in order to show that it points
at each instant of time
in the direction
of the center of the circle which
is described by the particle.
The magnitude of the
velocity vector a can be obtained by evaluation of its modulus.
|a|
= √( ( -ω2R cos(ωt) )2
+ ( -ω2R sin(ωt) )2 )
= ω2R
Hence, the acceleration
of the particle equals ω2R.
|
|
