In the above video we have attached the
velocity vector v to the particle,
in order to show that it points
at each instant of time
in the direction of the motion
of the particle, tangential
to the circle it describes.
The magnitude of the
velocity vector v can be obtained by evaluation of its modulus.
|v|
= √( ( -ωR sin(ωt) )2
+ ( ωR cos(ωt) )2 )
= ωR
Hence, the speed
of the particle equals ωR.
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